[HN Gopher] Weighing a Car with Tire Pressures
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       Weighing a Car with Tire Pressures
        
       Author : as89
       Score  : 34 points
       Date   : 2020-06-29 21:22 UTC (1 hours ago)
        
 (HTM) web link (surjan.substack.com)
 (TXT) w3m dump (surjan.substack.com)
        
       | cryptoz wrote:
       | You can weigh small objects with most smartphones with decent
       | accuracy these days using the barometer. Put your phone into a
       | ziplock bag, blow full of air, zip closed. Take a small object
       | with known weight to calibrate your scale. Carefully place the
       | object on the ziplock bag with your phone inside. The barometer
       | in your phone can measure the air pressure change by having the
       | weight placed on top of the bag. Knowing the weight of your first
       | object and the change in pressure observed, you can calibrate the
       | scale to know how much pressure change correlates to weight
       | placed on top.
       | 
       | Then you can weigh arbitrary objects using your phone! Be
       | careful, don't break your phone (don't try to stand on it to
       | weigh yourself!)
        
       | kyleblarson wrote:
       | Wasn't there a Feynman story where he did this exact same thing?
        
       | jaxx75 wrote:
       | Assuming all tires are the same, I think this would be most
       | applicable for weight distribution alone, but not really for the
       | weight. For performance applications, distribution is of course
       | 
       | The author also did not ensure the ground was level, which of
       | course would have an effect on the weight distribution.
        
       | guygurari wrote:
       | The suggestion is to use F=PA to measure the car weight, where P
       | is the tire pressure, A is the area the tires in contact with the
       | ground, and F is the unknown: the weight of the car (measured in
       | terms of gravitational force).
       | 
       | I don't think this works. To see why, suppose we make the tires
       | out of a very stiff material. We control the pressure P, but
       | changing the pressure will not change the surface area A.
       | Therefore, by changing P we can set F to whatever we want, which
       | shows that we are not actually measuring the weight of the car.
       | The basic issue here is that the air pressure is not the only
       | thing that is supporting the car.
       | 
       | I don't know how important the stiffness effect is for real
       | tires, but I suspect they are sufficiently stiff that it matters
       | a lot.
        
         | tmoney1818 wrote:
         | I think he nixes your case at the start, when he goes through
         | the sanity check thinking about the flat tire. Also, I think
         | your rigid body case use the walls of the tires to apply force
         | to the care, not the force from the pressure to keep the car
         | static, which is why it fails.
        
           | guygurari wrote:
           | I agree that higher tire pressure results in smaller surface
           | area, but it's not clear to me that the tire itself does not
           | support the car, skewing the result. So I'm not convinced
           | this sanity check is sufficient. For example, as another
           | commenter mentioned, run-flat tires can support the car on
           | stiffness alone.
        
             | abstrakraft wrote:
             | I agree, the sanity check is not sufficient. It confirms
             | the concept that as pressure decreases, area increases, but
             | is not sufficient to confirm a linear relationship. In the
             | limit, the area clearly does not become infinite when
             | pressure drops to 0.
             | 
             | For the case you suggested above, this is essentially how
             | run-flat tires work. Of course, the sidewall of the tire
             | isn't as stiff as the support ring, but they do provide
             | some support.
        
         | Gunax wrote:
         | > I don't know how important the stiffness effect is for real
         | tires, but I suspect they are sufficiently stiff that it
         | matters a lot.
         | 
         | It's odd, because as I was reading your comment, I was thinking
         | the exact opposite. I am considering the force it takes to
         | squish a flat tire. A person can squish a (regular car's) flat
         | tire with his/her hands.
         | 
         | My gut-check tells me that the stiffness of each tire can lift
         | less than 10kg/20lbs... multiplied by 4, that still is not a
         | huge contributor to the overall weight.
        
           | guygurari wrote:
           | It's certainly possible my intuition is wrong. Run-flat tires
           | can support the whole car, but it is possible this support
           | only kicks in at very low pressure.
        
       | sm4rk0 wrote:
       | A genuine hacker!
        
       | swsh wrote:
       | Pretty difficult to get any form of accuracy with this because
       | you can't easily account for tyre sidewall stiffness
        
         | nickff wrote:
         | How does sidewall stiffness matter? The ground is holding the
         | car up; the air is not.
        
           | JoshuaDavid wrote:
           | In the case of a perfectly rigid sidewall, the internal air
           | pressure could be 0 and the car would still be held up.
        
           | phkahler wrote:
           | The quickest way to realize the contribution: Imagine the
           | tire is made of steel so it does not deform when the air is
           | let out. This would be terrible to drive on, but it would not
           | require inflation even though it's hollow like a rubber tire.
           | A rubber tire will usually not "go flat" even with the
           | rims/wheel installed even without pressure (aside from
           | atmospheric which is present when it's put on the rim). So
           | some load is supported by the structure of the tire itself
           | through the side walls. How much will vary with the tire.
        
       | dognotdog wrote:
       | Kudos, for My first inclination would've been to jack up the car
       | and look at pressure differences of unloaded vs. loaded tyres...
       | then look at loaded wheel center height above ground vs. nominal
       | radius, compute the the reduction in volume, and assume contact
       | patch to be the area of the flattened section of the tyre
       | cylinder... giving me a whole lot of parameters with wild
       | inaccuracies and probably equally wild results :)
        
       | function_seven wrote:
       | How much does tire sidewall stiffness contribute to the force
       | holding the car up? I know that can vary a lot. Some cars have
       | run-flats that won't sag when they lose pressure (or won't sag as
       | much, anyway). Low profile tires probably transfer more of the
       | load through the sidewall than doughnut tires.
       | 
       | And of course the contribution from the sidewalls (as a percent)
       | will change as tire pressure increases.
        
         | surjansingh wrote:
         | Oops that's a great point. I completely forgot about sidewall
         | stiffness. My messing around with treads was probably just me
         | adjusting things to make myself look good then!
        
       | danbr wrote:
       | Upvoted for the Saab
        
       | JoshuaDavid wrote:
       | I wonder if you could do even better by putting paint or ink on
       | the outside of the tire, driving over a piece of paper, and
       | seeing what fraction of the paper touched your tire (and thus
       | what fraction of the rectangle boundary actually touches the
       | ground).
        
         | dmurray wrote:
         | And to measure how much of the grooves are in contact with the
         | ground, you could add a known weight to the car (like 100kg of
         | people), measure it with and without that weight and see what
         | proportion of the grooves you need to account for to get 100kg
         | difference.
         | 
         | You'd get better accuracy from a bigger added weight, but the
         | bigger the added weight the more you risk changing what you're
         | measuring by forcing more tire rubber into contact with the
         | ground.
        
         | nickff wrote:
         | You'd basically just be measuring the maximum width of the
         | contact patch, not its area. The best solution would be to lift
         | up each tire, put a piece of paper under it, let the car down,
         | then remove it, measuring the darkened area.
        
       | aj7 wrote:
       | Remarkably inaccurate.
       | 
       | This is a negative result.
        
       | YarickR2 wrote:
       | Well, the idea is nice, but, as others have said, we need to
       | account for sidewall stiffness. But we can do better with law of
       | large numbers and employing metering tape to measure difference
       | in car height with different pressure in tires. First we need to
       | collect baseline data - tire brand, model and size, tire
       | pressure, and car height difference , for known car weights, for
       | two different pressures (say, 20 and 35 psi), this way we could
       | deduce tire sidewall stiffness for given make/model/size of the
       | tire. After that we can do the same for all cars with same tires,
       | by measuring car height difference between two pressure points.
       | Measuring height changes on both axles (wheel center to lowest
       | point of the wheel arch) will get us weight distribution ; but
       | we'll need to account for staggered tire setup .
        
       | ordx wrote:
       | Can moderators remove utm codes from the url?
        
         | dang wrote:
         | Ok. Submitted URL was
         | https://surjan.substack.com/p/16-weighing-a-car-with-tire-
         | pr....
        
       | serf wrote:
       | a similar was (maybe is) used by the California Highway Patrol to
       | determine whether or not truck drivers are carrying too heavy a
       | load, or too heavy a load down specific streets or highways.
       | 
       | my father was erroneously pulled over by a CHP that used a
       | similar method, taken to a weigh-scale, and was actually under-
       | weight. Wooops!
        
       | abstrakraft wrote:
       | This method doesn't account for the support of the tire itself
       | through the sidewalls, as opposed to the pressure contained
       | within it.
       | 
       | You should be able to estimate this contribution by fitting to
       | the curve of area vs pressure at lower pressures. For example,
       | the linear F=PA relationship clearly breaks down at 0 pressure,
       | as F>0 and A>0 when P=0.
        
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       (page generated 2020-06-29 23:00 UTC)